Calculate the electric energy flowing into the filament of an electric bulb in 20 secs, when it's resistance is 40ohm and potential differance across it's terminal is 12V?

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Answer 1 · 2018-05-25T11:29:14

The energy is #=72J#

Ohm's Law is

#U=RI#

The power is

#P=UI=U^2/R#

The voltage is #U=12V#

The resistance is #R=40 Omega#

The power is

#P=12^2/40=3.6W#

The energy is

#W=Pt=3.6xx20=72J#