Calculate the heat required to change 76g of water at 23c to 100c?

1 Answer
Junaid Mirza
Apr 23, 2018

Approximately #"24.48 kJ"#

Explanation:

Use this equation

#"Q = mC"Δ"T"#

where

  • #"Q ="# Heat
  • #"m ="# Mass of sample
  • #"C ="# Specific heat of sample (#"4.184 J/g°C"# for water)
  • #"ΔT ="# Change in temperature

#"Q" = 76 cancel"g" × "4.184 J"/(cancel"g" cancel"°C") × (100 - 23) cancel"°C" = "24484.768 J" ≈ "24.48 kJ"#

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