# Calculate the heat required to raise the temperature of 0.75 kg of water from 5˚C to 90.˚C?

Jan 28, 2017

This will require $266.9 k J$ of heat energy.

#### Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material, $m$

The temperature change that occurs, $\Delta T$

The specific heat capacity of the material, $c$ (which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.

Here is a source of values of $c$ for different substances:

http://www2.ucdsb.on.ca/tiss/stretton/Database/Specific_Heat_Capacity_Table.html

Once you have all that, this is the equation:

$Q = m \times c \times \Delta T$

($Q$ is usually used to symbolize that heat required in a case like this.)

For water, the value of $c$ is 4.186 J/(g°C)

So, $Q = 750 \times 4.186 \times 85 = 266 858 J = 266.858 k J$