Calculate the mass in kilograms of #2.6xx10^23# molecules of #"SO"_2# ?

1 Answer
Jun 10, 2018

Answer:

#"0.028 kg"#

Explanation:

We were given #2.6 xx 10^23# molecules of #"SO"_2#. That means that

#N = 2.6 xx 10^23 \ "molecules"#

Use

#n ("number of moles") = N/(N_A ("Avogadro's constant"))#

to get

#n = (2.6 xx 10^23\ "molecules") / (6.02 xx 10^23\ "molecules/mol") = "0.432 moles"#

Now use

#m = n xx M ("molar mass")#

to get

#m = "0.432 mol" xx "64.066 g/mol" = "27.677 g"#

So

#m ("in kilograms") = "27.677 g" / (10^3 \ "g/kg") = "0.028 kg"#