Question

Calculate the mass of silver nitrate needed to prepare a solution of 0.02 mol/L?

Answer 1

Around `3.4` grams of silver nitrate per liter of the solution.

Explanation:

I'm assuming that you want to prepare `1 \ "L"` of an aqueous silver nitrate solution with a concentration of `0.02 \ "M"`.

Since the concentration is `0.02 \ "M"`, and we need to prepare `1 \ "L"` of the solution, we would use `0.02 \ "mol"` of silver nitrate.

Silver nitrate has a molar mass of `169.87 \ "g/mol"`.

So here, we would need,

`0.02color(red)cancelcolor(black)"mol"*(169.87 \ "g")/(color(red)cancelcolor(black)"mol")~~3.4 \ "g"`