Question

Calculate the mass of zinc oxide that is obtained from decomposition of 9,95 g of zinc hydroxide . the yield of the reaction is 80%.?

Answer 1

`"Mass of zinc oxide = 6.52 g"`

Explanation:

We need (i) a stoichiometrically balanced equation...

`Zn(OH)_2(s) stackrelDeltararrZnO(s) + H_2O(l)`..

And (ii) equivalent quantities of zinc hydroxide...

`n_(Zn(OH)_2)=(9.96*g)/(99.42*g*mol^-1)=0.100*mol`

And so with respect to zinc oxide, we gets a mass of....

`80%xx0.100*molxx81.38*g*mol^-1=6.52*g`...