Calculate the masses of solid sodium and gaseous nitrogen required for the production of #"100g"# of sodium nitride. Assume that all reactants are consumed and that the yield is 100%. #"6Na + N"_2"##rarr##"2Na"_3"N"#?

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Answer 1 · 2018-06-18T19:25:26

Well.....we address the equation...#1/2N_2(g) + 3Na(s) stackrel(Delta)rarrNa_3N(s)#

#"Moles of sodium nitride"=(100*g)/(82.98*g*mol^-1)=1.205*mol#.

And thus we need equivalent quantities of metal and dinitrogen...

#"Moles of dinitrogen"-=1.205*molxx1/2xx28.02*g*mol^-1=16.88*g#

#"Moles of metal"-=1.205*molxx3xx22.99*g*mol^-1=83.12*g#...

We could measure the mass of the metal...we would have difficulty introducing stoichiometric dinitrogen....

Why should the masses of the metal and dinitrogen add up to #100*g#? Do they?