Calculate the molarity of a solution made from 125g of CaCl2 in 175mL of solution?

1 Answer
anor277
Jan 21, 2018

#[CaCl_2(aq)]~=13*mol*L^-1#

Explanation:

By definition....#"concentration"-="Moles of solute"/"Volume of solution"#

And so we got...#((125*g)/(110.98*g*mol^-1*g*mol^-1))/(175xx10^-3*L)=12.9*mol*L^-1#...

This is probably right at the limit of saturation....and I hope the question draws from actual data, rather than from the teacher's arse.

What is #[Cl^-]# in the given solution?

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