Calculate the molarity of the solution that would result if u diluted 5.00mL of concentrated nitric acid to 250.0mL?

Does anyone no the answer I've been working on it for hourz

1 Answer
Apr 6, 2018

Well, yes, but you need to know the concentration of the nitric acid, the which you have not specified.

Explanation:

The basic equation is...#"concentration"="moles of solute"/"volume of solution"#.

The most concentrated nitric acid you can buy is #70%# #HNO_3#, the which has a density of #1.42*g*cm^-3#...these data SHOULD have been supplied with the question.

And so we take the quotient to get the molar concentration...and we use a #1*mL# volume..

#[HNO_3(aq)]=((1.42*gxx70%)/underbrace(63.01*g*mol^-1)_"molar mass of nitric acid")/(1xx10^-3*L)=15.8*mol*L^-1#

And so we use the defining quotient again with respect to the new volume....

#[HNO_3]=(5.00*mLxx10^-3*L*mL^-1xx15.8*mol*L^-1)/(250.0*mLxx10^-3*L*mL^-1)#

#=0.316*mol*L^-1#...