Calculate the number of recessive allele in hardy weinberg population of 200 individuals if frequency of dominant allele is 0.7?

1 Answer
Apr 23, 2018

#p=0.3=30%=60#

Explanation:

Hardy-Weinberg equation states that,

#p^2+2pq+q^2=1#

  • #p# is the number of recessive alleles

  • #q# is the number of dominant alleles

  • #2pq# is the frequency of the heterozygous genotype

Factoring, we get,

#(p+q)^2=1#

We are given that: #q=0.7#.

#:.(p+0.7)^2=1#

#p+0.7=sqrt(1)=1# #(because \ "the sum must be positive")#

#=>p=1-0.7#

#=0.3#

Since #30%# will have the recessive allele, then in a population of #200# organisms, there will be #200*30%=60# who will have the recessive allele.