Calculate the probability of flipping a coin 20 times and getting 4 heads. Round your answer to the nearest ten thousandth?

1 Answer

#0.0046#

Explanation:

I'm going to assume you know binomial probability, with the general form of:

#sum_(k=0)^(n)C_(n,k)(p)^k((~p)^(n-k))#

We're flipping a coin 20 times #(n=20)# and we want 4 heads #(k=4)#. The probability of getting heads on any given roll is #0.5#, therefore #p=0.5#. This means that the probability of not getting heads is also #0.5#, and so #~p=0.5#:

#C_(20,4)(.5)^4((.5)^(16))=4845xx0.0625xx0.00001525878=0.00462055206~~0.0046#