# Calculate the volume of .00500 M solution needed to make 10.00 ml of the following? .00400 M solution .00300 M solution

Jul 5, 2017

${V}_{1} = 8.00$ $\text{mL}$

${V}_{2} = 6.00$ $\text{mL}$

#### Explanation:

To solve these problems, we can use the dilution equation

${M}_{\text{conc"V_"conc" = M_"dil"V_"dil}}$

where

• $M$ is the molarity of the concentrated ($\text{conc}$) and dilute ($\text{dil}$) solutions

• $V$ is the volume of the concentrated and dilute solutions

The volume needed for the first concentration ($0.00400 M$) is

V_"conc" = (M_"dil"V_"dil")/(M_"conc")

= ((0.00400cancel(M))(10.00color(white)(l)"mL"))/(0.00500cancel(M)) = color(red)(8.00 color(red)("mL"

and the second concentration ($0.00300 M$):

V_"conc" = ((0.00300cancel(M))(10.00color(white)(l)"mL"))/(0.00500cancel(M)) = color(blue)(6.00 color(blue)("mL"

Jul 5, 2017

Molarity x Volume (concentrate) = Molarity x Volume (diluted)

(0.005M)Vol Conc = (10ml)(0.004M)
=> Vol Concentrate = [(10ml)(0.004M)/(0.005M)] = 8 ml

Mixing => Transfer 8 ml of 0.005M concentrate into mixing container and dilute up to but not to exceed 10 ml total volume=> 0.004M Soln

(0.005M)Vol Conc = (10ml)(0.003M)
=> Vol Concentrate = [(10ml)(0.003M)/(0.005M)] = 6 ml

Mixing => Transfer 6 ml of 0.005M concentrate into mixing container and dilute up to but not to exceed 10 ml total volume=> 0.003M Soln