# Can any1 help me in 11 phy question... The percentage error in the momentum is 100% Wt is the percentage error in the kinetic energy??

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Jane Share
Feb 7, 2018

Kinetic energy ($E$) of a particle with mass $m$ having momentum $P$ is related as,

$E = {P}^{2} / \left(2 m\right)$

As, $m$ is constant,

So,we can write,

$\frac{\delta E}{E} = 2 \cdot \frac{\delta P}{P}$

Given, $\frac{\delta P}{P} \cdot 100 = 100$

So, $\frac{\delta E}{E} \cdot 100 = 2 \cdot 100 = 200$

So,percentage error in kinetic energy will be $200$

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