Question

Can anybody know how to solve this trigonometry problem???

Answer 1

We know that,
`sintheta=` side opposite to `theta` / hypotenuse
`costheta=` side adjacent to `theta` / hypotenuse
`tantheta=` side opposite to `theta` / side adjacent to `theta`

Explanation:

`In triangleTAG,(TA)^2+(AG)^2=8^2+6^2=64+36=100`
`and(TG)^2=10^2=100=>(TA)^2+(AG)^2=(TG)^2`
`=>mangleA=90^0=pi/2`
`(1)sinT=(AG)/(TG)=6/10=3/5`
`(2)cosA=cos(pi/2)=0`
`(3)tanG=(TA)/(AG)=8/6=4/3`
`(4)cscT=(TG)/(AG)=10/6=5/3`
`(5)cotG=(AG)/(TA)=6/8=3/4`
`(6)secA=sec(pi/2)=` undefined
`(7)sinA=sin(pi/2)=1`
`(8)cotA=cot(pi/2)=0`
`(9)cscG=(TG)/(TA)=10/8=5/4`
`(10)tanA=tan(pi/2)=` undefined