Can someone help me with this question?

Question

1780 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-13T18:58:38

#y=108^@#

enter image source here

On the diagram:

#/_1 = /_2# and #/_3=/_4#

These are called corresponding angles.

Using #/_3=/_4#

#3x-12^@=2x+16^@#

#x=28^@#

Now:

#/_1+/_3=180^@# angles on a straight line:

#:.#

#y+3x-12^@=180^@#

From above: #x=28^@#, so:

#y+3(28^@)-12^@=180^@#

#y+72^@=180@#

#y=108^@#