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Consider a cylindrical nickel wire 2.7 mm in diameter and 2.0 * 104 mm long. Calculate its elongation (in mm) when a load of 400 N is applied. Assume that the deformation is totally elastic.

Modulus of Elasticity for nickel is 158 GPa.

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1 Answer
Stan
Apr 19, 2018

#DeltaL=8.88296m#... #DeltaL=8882.9mm#

Explanation:

Use #F/A=Y(DeltaL)/(L_0# which relates Youngs Modulus with Tensile Stress and Tensile Strength . Since diameter equals 2.7 mm, #r=1.3*10^-3#m . Use #A=pir^2# and solve for #DeltaL# using the known force of 400 N and #L_0=20m# after converting #2*10^4mm# to meters and converting #158GPa# to #158000N/m^2#.

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