Can someone help solve #4^(2x-3) = 5^x# ?

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Answer 1 · 2017-11-11T13:25:51

#x = 3.5754#

#4^(2x-3) = 5^x#

Taking Log on both sides,
#Log (4^(2x-3)) = Log 5^x#

#(2x-3) Log 4 = x Log 5#

#(2x-3)* 0.6021 = x * 0.6990#

Taking x terms to L H S & Constant term to R H S,

#1.2042x - 0.6990 x = 3 * 0.6021#

#(1.2042 - 0.6990) x = 1.8063#

#x = 1.8063 / 0.5052 = 3.5754#