Can someone please help me figure out F(u) ? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer RedRobin9688 Jun 27, 2018 #f(u)=1/6u^3# Explanation: #int_1^5((6x-2)^3)dx# Let #u=6x-2# then #(du)/6=dx# Find new bounds #u=6(1)-2=4, u=6(5)-2=28# #int_1^5((6x-2)^3)dx = int_4^28(1/6u^3)du# #f(u)=1/6u^3# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 1390 views around the world You can reuse this answer Creative Commons License