Can someone please help me with this question?

1 Answer

#28xx(1/2)^6xx(1/2)^2~~10.94%#

Explanation:

The question is that a coin is tossed 8 times and we're looking for the probability of exactly 6 tails.

Let's work the question this way - first off we know that the probability of getting tails is #1/2# on any given flip. We want exactly 6 of them, so that's #(1/2)^6#.

We also have to account for not getting tails - the probability of not getting tails on any given flip is also #1/2# and we want exactly 2 of them, so that's #(1/2)^2#.

Lastly, there are a number of different ways we can get 6 T and 2 H:

TTTTTTHH
HHTTTTTT

and so on. In fact, there are #((8),(6))# ways of getting 6 Tails and 2 Heads. That's #((8),(6))=28#.

In all then, we have:

#28xx(1/2)^6xx(1/2)^2~~10.94%#