# Can someone please help with this **logarithms** question?

##### 1 Answer

May 18, 2018

Use properties of logarithms for all of the following.

i)

#log_p sqrt(x) = log_p x^(1/2) = 1/2log_p x = 9/2# ii)

#log_p (1/x) = log_p 1 - log_p x = 0 - 9 = -9# iii)

#log_p(xy) = log_p x + log_p y = 9 + 6 = 15# iv)

#log_y x = logx/logy = log_p x/log_p y = 9/6 = 3/2#

Hopefully this helps!