Question

can u help me write an equation in point-slope form for the line through the given point with the given slope? (9, –1); m = 4/3

Answer 1

`y+1=4/3(x-9)`

Explanation:

`"the equation of a line in "color(blue)"point-slope form"` is.

`•color(white)(x)y-b=m(x-a)`

`"where m is the slope and "(a,b)" a point on the line"`

`"here "m=4/3" and "(a,b)=(9,-1)`

`"substitute these values into the equation"`

`y-(-1)=4/3(x-9)`

`y+1=4/3(x-9)larrcolor(red)"in point-slope form"`

Answer 2

See explanation below

Explanation:

General line equation in point slope form is given by

`y-y_0=m(x-x_0)` where `m` is slope and `(x_0,y_0)` passing point

In our case we have `(x_0,y_0)=(9,-1)` and `m=4/3`. Then

`y-(-1)=3/4(x-9)`. this is the equation point-slope

Usually, we operate this expresion

`y+1=3/4x-27/4`

`y=3/4x-27/4-1`

`y=3/4x-31/4` or `y=1/4(3x-31)`