# Can y=2x^2+9x-5 be factored? If so what are the factors ?

$y = 2 {x}^{2} + 9 x - 5 =$2(x + p)(x + q)
Converted trinomial $y ' = {x}^{2} + 9 x - 10 =$ (x + p')(x + q').
Back to y, $p = - \frac{1}{2}$ and q = 10/2 = 5
$y = 2 \left(x - \frac{1}{2}\right) \left(x + 5\right) = \left(2 x - 1\right) \left(x + 5\right)$