# Can y=7x^3-4x^2+8x  be factored? If so what are the factors ?

##### 1 Answer
Dec 17, 2015

Factor $y = 7 {x}^{3} - 4 {x}^{2} + 8 x$

#### Explanation:

$y = x Y = x \left(7 {x}^{2} - 4 x + 8\right)$. Factor Y.
D = b^2 - 4ac = 16 - 224 < 0. Since D < 0, there are no real roots, therefor, Y can't be factored.
Finally: $y = x \left(7 {x}^{2} - 4 x + 8\right)$