Can you help with Q6?

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-Fish

1 Answer
Sep 2, 2017

Surface area #=7902.99 " cm"^2#

Explanation:

Let #SA_1, SA_2, and SA_3# be the lateral area of the cone, the lateral area of the cylinder, and the area of the base of the cylinder, respectively.

1) #SA_1=pirsqrt(h^2+r^2)#, where #h# and #r# are the height and the radius of the cone, respectively.
#=> SA_1=pixx12xxsqrt(18^2+12^2)=24sqrt117pi " cm"^2#

2) #SA_2=2pirxxh'#, where #h'# and #r# are the height and the radius of the cylinder, respectively.
#=> SA_2=2xxpixx12xx88=2112pi " cm"^2#

3) #SA_3=pir^2=pixx12^2=144pi#

Hence, total surface area of the object
#=SA_1+SA_2+SA_3#
#=24sqrt117pi+2112pi+144pi#
#=pi(24sqrt117+2112+144)#
#=7902.99 " cm"^2# (2.d.p.)