Can you prove the following identity? cosx+tanx/sinx*cosx= cosx+sec^2xb-

1 Answer
May 1, 2018

See below

Explanation:

Using:
#tanx= sinx/cosx#
#secx=1/cosx#

Start:
#cosx+tanx/(sinx*cosx)= cosx+sec^2x#

#cosx+cancelsinx/cosx*1/(cancelsinx*cosx)= cosx+sec^2x#

#cosx+1/cos^2x= cosx+sec^2x#

#cosx+sec^2x=cosx+sec^2x#