Can you write the equation in standard form for the circle with center (0,3) passing through (0,9/2)?
Algebra 2
Algebra 2
1 Answer
Apr 26, 2018
Explanation:
#"the equation of a circle in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"is the radius"#
#"here "(a,b)=(0,3)" but we require r"#
#"the radius is the distance from the centre to the given"#
#"point on the circumference "(0,9/2)#
#"since the x-coordinates of both points are zero then "#
#"substituting into the equation gives"#
#(x-0)^2+(y-3)^2=(3/2)^2#
#rArrx^2+(y-3)^2=9/4larrcolor(red)"equation of circle"#