Car accelerates from rest under constant tractive force of 100N. After travelling 300m engine stalls and car slows down to a stop, without applying brakes. Throughout the motion there is a constant resistance of 30N, what is the distance travelled?
A car accelerates from rest under the constant tractive force of 100N. After travelling 300m the engine stalls and the car slow down to a stop, without the application of the brakes. If, throughout the motion, there is a constant resistance of 30N, find the total distance travelled.
A car accelerates from rest under the constant tractive force of 100N. After travelling 300m the engine stalls and the car slow down to a stop, without the application of the brakes. If, throughout the motion, there is a constant resistance of 30N, find the total distance travelled.
1 Answer
Let
Using Newton's Second Law of motion, Forward constant acceleration
Using following kinematic expression to find maximum velocity attained
#v^2-u^2=2as# ........(1)
#v_max^2-0^2=2xx100/Mxx300#
#=>v_max^2=60000/M\ m^2s^-2# ........(2)
After engine stalls, retardation
Using (1) we get
#0^2-v_max^2=2xx(-30/M)xxs_2#
where#s_2# is distance traveled during decelerated motion till car stops.
#=>v_max^2=60/Mxxs_2#
Using (2) we get
#60000/M=60/M s_2#
#=>s_2=60000/60=1000\ m#
Total distance traveled (rest to stop)
