Question

Integrate `cos(t+pi/4)` in `[0,pi/2]`?

Answer 1

`int_0^(pi/2) cos(t+pi/4)*dt=0`

Explanation:

`int_0^(pi/2) cos(t+pi/4)*dt`

=`[sin(t+pi/4)]_0^(pi/2)`

=`sin(3pi/4)-sin(pi/4)`

=`(sqrt2)/2-(sqrt2)/2`

=`0`