Complete the square: #color(white)("d")m^2+20m=-5# How would you work this one out? (I don’t know how to do it if the c value is missing)

2 Answers
Nov 8, 2017

#(m+10)^2-95=0#

Explanation:

#"to "color(blue)"complete the square"#

#• " ensure the coefficient of the squared term is 1"#

#m^2+20m=-5larr"coefficient of "m^2" is 1"#

#• " add "(1/2"coefficient of m term")^2" to both sides"#

#m^2+2(10)mcolor(red)(+100)=-5color(red)(+100)#

#=(m+10)^2=95#

#"or "(m+10)^2-95=0#

Nov 8, 2017

See explanation
Observe that in the graph both

#color(red)(m^2+20m+5=0) and color(blue)((m+10)^2-95=0)#

Are the same thing. They completely overlap.

Explanation:

For a very in-depth explanation of the method have a look at my solution: https://socratic.org/s/aKFa5Suf

In this case the c is there but it is 'hidden'. In that it looks like the value for #y#

Add #5# to both sides giving

#m^2+20m+5=0#

Set as #m^2+20m+5=0=y#

Solve for #y=0#

Write as #(m^2+20m)+k+5=0#

Take the power outside the brackets

#(m+20m)^2+k+5=0#

Remove the m from #20m#

#(m+20)^2+k+5=0#

Halve the 20

#(m+10)^2+k+5=0#

In making these changes we have introduced a value that is not in the original equation. So we need to remove it (subtraction). This is where #k# comes in.

Set #10^2+k=0 => k=-100#

#(m+10)^2-100+5=0#

#(m+10)^2-95=0 larr" The question only askes for this stage"#

Tony B