Consider the polar curve r = 2 + sin(3theta). Determine the Cartesian equation (in slopeintercept form) of the line tangent to the curve at the Cartesian point (2,0). (?)
First of all, the wording of the problem has me very confused. I don't know exactly what I'm supposed to find; y? or dy/dx ? But I gave it a go and this is what I got:
I used sin(3theta) = 3sin(theta)  4sin^3(theta) to get
r = 2 + 3sin(theta)  4sin^3(theta)
then, I multiplied both sides by r
r^2 = 2r + 3rsin(theta)  4rsin^3(theta)
I substituted using the formulas x = rcos(theta), y = ...
First of all, the wording of the problem has me very confused. I don't know exactly what I'm supposed to find; y? or dy/dx ? But I gave it a go and this is what I got:
I used sin(3theta) = 3sin(theta)  4sin^3(theta) to get
r = 2 + 3sin(theta)  4sin^3(theta)
then, I multiplied both sides by r
r^2 = 2r + 3rsin(theta)  4rsin^3(theta)
I substituted using the formulas x = rcos(theta), y = ...
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@devitt25 Devitt25 asked the question.

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