# Consider this quadratic function f(x)=2x^2-8x+1, how do you find the axis of symmetry?

Nov 12, 2016

The equation of the axis of symmetry for $f \left(x\right) = 2 {x}^{2} - 8 x + 1$ is $x = 2$.

#### Explanation:

This quadratic function is in standard form, $f \left(x\right) = a {x}^{2} + b x + c$.
For every quadratic function in standard form the axis of symmetry is given by the formula $x = \frac{- b}{2 a}$.

In $f \left(x\right) = 2 {x}^{2} - 8 x + 1$, $a = 2$, $b = - 8$, and $c = 1$. So, the equation for the axis of symmetry is given by

$x = \frac{- \left(- 8\right)}{2 \cdot 2}$

$x = \frac{8}{4}$

$x = 2$