Cos(2sin inverse X)=?

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Answer 1 · 2018-04-18T06:18:40

#cos(2sin^-1x)=1-2x^2#

Let,

#y=cos(2sin^-1x)#

Take,

#sin^-1x=theta=>x=sintheta#

#:.y=cos(2theta)#

#=>y=1-2sin^2theta#

#=>y=1-2(sintheta)^2#

#=>y=1-2x^2,where,y=cos(2sin^-1x)#

#=>cos(2sin^-1x)=1-2x^2#