YOUR QUESTION.:
#CosA cotA/1-sinA=1+cosecA#
#"I THINK YOU HAVE DONE SOME PRINTING MISTAKE."#
#"Answer for the question:"#
#color(violet)((CosA cotA)/(1-sinA)=1+cosecA)#
Take,
#LHS=(CosA color(blue)(cotA))/(1-sinA)#
#=(cosAcolor(blue)((cosA/sinA)))/(1-sinA)...to[as,color(blue)(cotA=cosA/sinA)]#
#=color(red)(cos^2A)/(sinA(1-sinA) )...to[where, color(red)(cos^2A=1-sin^2A) ]#
#=color(red)((1-sin^2A))/(sinA(1-sinA)#
#=(cancel((1-sinA))(1+sinA))/(sinAcancel((1-sinA)))#
#=(1+sinA)/sinA#
#=1/sinA+sinA/sinA#
#=cosecA+1#
#=RHS#