Question

Cosecx/cosecx-sinx=sec^x?

Answer 1

Please see the proof below

Explanation:

We need

`cscx=1/sinx`

`sin^2x+cos^2x=1`

`1/cosx=secx`

Therefore,

`LHS=cscx/(cscx-sinx)`

`=((1/sinx)/(1/sinx-sinx))`

`=1/(1-sin^2x)`

`=1/cos^2x`

`=sec^2x`

`=RHS`

`QED`