Cosx=1-tan^2(x/2)/1+tan^2(x/2)?

1 Answer
Mar 27, 2018

#Cosx=(1-tan^2(x/2))/(1+tan^2(x/2))#

#Cosx=(1-((1-cosx)/sinx)^2)/(1+((1-cosx)/sinx)^2)#

#Cosx=(1-((1-2cosx+cos^2x)/sin^2x))/(1+((1-2cosx+cos^2x)/sin^2x))#

#Cosx=(sin^2x/sin^2x-((1-2cosx+cos^2x)/sin^2x))/(sin^2x/sin^2x+((1-2cosx+cos^2x)/sin^2x))#

#Cosx=((2cosx-2cos^2x)/sin^2x)/((2-2cosx)/sin^2x)#

#Cosx=(cancel(2)cosxcancel((1-cosx)))/cancel(sin^2x)*cancel(sin^2x)/(cancel2cancel((1-cosx))#

#cosx=cosx#