#cos(x)cot(x)=0#?

1 Answer
Apr 7, 2018

#x = pi/2+npi, n in ZZ#

Explanation:

Given: #cos(x)cot(x)=0#

The above can only be true when:

#cos(x) = 0# or #cot(x) = 0#

Both of these occur at #x = pi/2# and repeats at integer multiples of #pi#:

#x = pi/2+npi, n in ZZ#