cot765^@ = cot765∘=? sec765^@ = sec765∘=? csc765^@ = csc765∘=?

2 Answers
Jim G.
Dec 1, 2017

1,sqrt2,sqrt21,√2,√2

Explanation:

"note that "765^@=765-720^@=45^@note that 765∘=765−720∘=45∘

rArrcot765^@=1/(tan45^@)=1/1=1⇒cot765∘=1tan45∘=11=1

rArrsec765^@=1/(cos45^@)=1/(1/sqrt2)=sqrt2⇒sec765∘=1cos45∘=11√2=√2

rArrcsc765^@=1/(sin45^@)=1/(1/sqrt2)=sqrt2⇒csc765∘=1sin45∘=11√2=√2

Evan
Dec 1, 2017

cot(45^@)=1cot(45∘)=1
sec(45^@)=sqrt2sec(45∘)=√2
csc(45^@)=sqrt2csc(45∘)=√2

Explanation:

Since, they are all in the same quadrant,

cot(765^@)=cot(45^@)=1cot(765∘)=cot(45∘)=1
sec(765^@)=sec(45^@)=sqrt2sec(765∘)=sec(45∘)=√2
csc(765^@)=csc(45^@)=sqrt2csc(765∘)=csc(45∘)=√2

With the help of this chart, we can, hence, easily solve the equation.

cot(45^@)=1cot(45∘)=1
sec(45^@)=sqrt2sec(45∘)=√2
csc(45^@)=sqrt2csc(45∘)=√2

![https://study.com/academy/lesson/http://trigonometric-function-values-of-special-angles.html](https://useruploads.socratic.org/E0bxHhKSTdW844KJXfeM_imagetrigfunctions9.jpg)

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