Derivative of square root of 3x using product rule?

1 Answer
Mar 11, 2018

Please see below.

Explanation:

I will guess that the intended function is #f(x)=sqrt(3x)#

We can write this as #f(x) = sqrt3 sqrtx#

Observe that #d/dx(sqrtx) = 1/(2sqrtx)#

#f(x) = FS# then #f'(x) = F'S+FS'# (the derivative of the first times the second, plus the first times the derivative of the second.)

#f'(x) = 0 * sqrtx + sqrt3 * 1/(2sqrtx) = sqrt3/(2sqrtx)#