# Determine the amount of water required to produce 500 ml of a solution that is 35% of alcohol dissolved in water?

Jul 4, 2018

325 mL

#### Explanation:

%"(v/v)"="volume of solute"/"volume of solution"*100%

From the question, alcohol is the solute and water is the solvent . Together, they combine to become solution .

Therefore,
$\text{volume of solute " = " volume of alcohol}$

$\text{volume of solution" = "volume of solute" + "volume in solvent" = "volume of alcohol" + "volume of water" = "500 mL}$

Plug in the given values into the percent volume formula to find the volume of alcohol,
%"(v/v)"="volume of solute"/"volume of solution"*100%

35%="volume of alcohol"/"500 mL"*100%

$\text{volume of alcohol" = ("35%"*"500 mL")/"100%"="175 mL}$

From the calculated volume of alcohol, we can now find the volume of water,

$\text{volume of solution" = "volume of alcohol" + "volume of water}$

$\text{500 mL" = "175 mL" + "volume of water}$

$\text{volume of water" = "500 mL" - "175 mL" = "325 mL}$