Determine the heat energy that must be added to bring 15 grams of water at 323K to 355K?

Determine the heat energy that must be added to bring 15 grams of water at 323K to 355K?

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Mar 10, 2018

Answer:

$\text{2016 Joule}$

Explanation:

$\text{Q = mC"Δ"T}$

Where,

$\text{Q =}$ Heat energy

$\text{m =}$ Mass of substance

$\text{C =}$ Specific Heat of substance (It is $\text{4.2 J/(g K)}$ for water)

Δ"T =" Change in temperature

$\text{Q" = "15 g" × "4.2 J"/"g K" × ("355 K" - "323 K") = "2016 Joule}$

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