# Determine the heat energy that must be added to bring 15 grams of water at 323K to 355K?

## Determine the heat energy that must be added to bring 15 grams of water at 323K to 355K?

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Mar 10, 2018

$\text{2016 Joule}$

#### Explanation:

$\text{Q = mC"Δ"T}$

Where,

$\text{Q =}$ Heat energy

$\text{m =}$ Mass of substance

$\text{C =}$ Specific Heat of substance (It is $\text{4.2 J/(g K)}$ for water)

Δ"T =" Change in temperature

$\text{Q" = "15 g" × "4.2 J"/"g K" × ("355 K" - "323 K") = "2016 Joule}$

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