Determine the temp. of 0.02 moles of a gas that occupies a volume of 100cm3 & at a pressure of 5x10^5Pa?

1 Answer
Junaid Mirza
Apr 18, 2018

#"300.5 K"#

Explanation:

  • Convert Presure in #"Pa"# to #"atm"#
    #5 × 10^5\ "Pa" = 5 × 10^5 cancel"Pa" × "1 atm"/(101325 cancel"Pa") = "4.935 atm"#

  • Convert Volume in #"cm"^3# to #"L"#
    #100\ "cm"^3 = 100 cancel("cm"^3) × "1 L"/(1000 cancel("cm"^3)) = "0.1 L"#

Use ideal gas equation

#"PV = nRT"#

#"T" = "PV"/"nR" = (4.935 cancel"atm" × 0.1 cancel"L")/(0.02 cancel"mol" × 0.0821 cancel"L" cancel"atm" // (cancel"mol" "K")) = "300.5 K"#

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