Determine the value of x to the nearest tenth of a centimeter?

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May 10, 2017

Answer:

x=68.2377 nearest tenth of a centimeter is 68.2 cms

Explanation:

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First consider the Right triangle ABC. BC= x sin 27

Next consider triangle DBC. Side DB=DC=27 (given). Now apply the cosine rule

Cos D=Cos 70=#(DB^2 +DC^2 -BC^2 )/(2 BD*DC)#

#cos 70 = (27^2 +27^2 -BC^2 )/(2 *27*27)#

#1458 cos 70= 729+729 -BC^2#

#BC^2 = 1458-1458 cos 70#

#(0. 4539 x)^2 = 1458- 1458( 0.34202)#

                     =959.3346

0.4539x= 30.9731

x= 68. 2377

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