Differentiate and simplify ??

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1 Answer
Feb 6, 2018

(a) #(df)/(dx)=(4x^11(8x+3))/(2x+1)^5#

(b) #(df)/(dx)=(e^xcos(sqrt(2e^x+1)))/sqrt(2e^x+1)#

Explanation:

(a) As #f(x)=(x^3/(2x+1))^4#

hence using first function of function rule (also called chain rule) and then quotient rule, we get the differential

#(df)/(dx)=4(x^3/(2x+1))^3xxd/dxx^3/(2x+1)#

= #4(x^3/(2x+1))^3xx(3x^2(2x+1)+x^3xx2)/(2x+1)^2#

= #4(x^3/(2x+1))^3xx(8x^3+3x^2)/(2x+1)^2#

= #(4x^9(8x^3+3x^2))/(2x+1)^5#

= #(4x^11(8x+3))/(2x+1)^5#

(b) Again using chain rule, as #f(x)=sin(sqrt(2e^x+1))#

#(df)/(dx)=cos(sqrt(2e^x+1))xxd/dx(sqrt(2e^x+1))#

= #cos(sqrt(2e^x+1))xx1/(2sqrt(2e^x+1))xxd/dx(2e^x+1)#

= #cos(sqrt(2e^x+1))xx1/(2sqrt(2e^x+1))xx2e^x#

= #(e^xcos(sqrt(2e^x+1)))/sqrt(2e^x+1)#