Differentiate the function? y = (ln(1 + e^x))^5 Calculus Basic Differentiation Rules Chain Rule 1 Answer Monzur R. Oct 1, 2017 #dy/dx=(5e^xln^4(1+e^x))/(1+e^x)# Explanation: #y=ln^5(1+e^x)# By the chain rule, #dy/dx=5ln^4(1+e^x)*d/dx[ln(1+e^x)]=5ln^4(1+e^x)*(d/dx(1+e^x))/(1+e^x)=(5e^xln^4(1+e^x))/(1+e^x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 3162 views around the world You can reuse this answer Creative Commons License