Differentiate #y^2 = 4ax# w.r.t #x# (Where a is a constant)?

1 Answer
Aug 2, 2017

# dy/dx = (2a)/(y) #

Explanation:

When we differentiate #y# wrt #x# we get #dy/dx#.

However, we only differentiate explicit functions of #y# wrt #x#. But if we apply the chain rule we can differentiate an implicit function of #y# wrt #y# but we must also multiply the result by #dy/dx#.

Example:

#d/dx(y^2) = d/dy(y^2)dy/dx = 2ydy/dx #

When this is done in situ it is known as implicit differentiation.

Now, we have:

# y^2=4ax \ \ \ #, the equation of a Parabola in standard form

Implicitly differentiating wrt #x#

# d/dx y^2 = d/dx 4ax #

# :. 2ydy/dx = 4a #

# :. dy/dx = (4a)/(2y) #

# :. dy/dx = (2a)/(y) #