Differentiate y = 9/(2x + 3?

1 Answer
May 8, 2018

dy/dx=-18/(2x+3)^2

Explanation:

"differentiate using the "color(blue)"chain rule"

"given "y=f(g(x))" then"

dy/dx=f'(g(x))xxg'(x)

"here "y=9/(2x+3)=9(2x+3)^-1

rArrdy/dx=-9(2x+3)^-2xxd/dx(2x+3)

color(white)(rArrdy/dx)=-9(2x+3)^-2xx2

color(white)(rArrdy/dx)=-18/(2x+3)^2