Does Li or F have the larger atomic radius?

1 Answer
Oct 31, 2015

Answer:

Lithium.

Explanation:

Start by taking a look at a periodic table and making a note of where lithium, #"Li"#, and fluorine, #"F"#, are located.

Notice that lithium is located in group 1 and fluorine is located in group 17 and, more importantly, they are both lcoated in period 2 of the periodic table.

This means that you can use your knowledge of the basic atomic structure to determine which atom will have the larger atomic radius.

So, you know that atomic number, which represents the number of protons that can be found in the nucleus of an atom, increases as you move from left to right across a period.

In your case, lithium has an atomic number equal to #3# and fluorine an atomic number equal to #9#. So fluorine has more protons in its nucleus. Keep this in mind.

Now, an atom's size is actually determined by how far away from the nucleus its outermost electrons are located.

Atoms that share a period have one important thing in common - their outermost electrons are located on the second energy level.

Here is where the number of protons that each atom has in its nucleus becomes important.

Since outermost electrons are located on the same energy level in both the lithium and the fluorine atoms, it follows that the nucleus that has more protons will attract these electrons more - this is known as effective nuclear charge.

So even if the outermost electron of lithium and the outermost electrons of fluorine reside on the same energy level, the latter will be more attracted to the nucleus, since fluorine has #9# protons there.

As a result, the atomic size of fluorine will be smaller than that of lithium, or, in other words, lithium will have larger atomic radius than fluorine.

http://www.webelements.com/periodicity/atomic_radius/period_2sp.html

Check this unbelievably cool video on periodic trends in atomic and ionic radius