# Does #sin180+sin45=sin225#?

##### 2 Answers

#### Answer:

Ehm...I do not think so...

#### Explanation:

I imagine the arguments in degrees so that if you plot your sin function you get:

As you can see:

while

I also considered the possibility to have them in radians but it doesn't work either...

#### Answer:

No

#### Explanation:

Remember that taking the

So the

**Think of it this way:**

#sqrt4 + sqrt25 = sqrt29#

#2+5=sqrt29#

#7cancel(=)sqrt29#

*In the same idea, #sin# does not work that way.*

Like Gio explained, the graphs are also different.

But how can you trust just plain words? Let's actually work out this problem.

#sin180# = 0

#sin(45) = sqrt2/2#

#sin225 = -sqrt2/2#

So:

#sin180 + sin45 = sin225#

#0 + sqrt2/2 cancel(=) -sqrt2/2#

And that's why you cant work with