Does the function #f(x) = 32(.5^x)# show growth or decay?

1 Answer
Apr 5, 2018

As the base #0.5# the base is less than #1#, it shows decay.

Explanation:

See #1.01^2=1.0201#, #1.01^3=1.030301#, #1.01^4=1.04060401#

and #0.99^2=0.9801#, #0.99^3=0.970299#, #0.99^4=0.96059601#

It is observed that even if the base is slightly higher than #1#, there is growth and even if the base is slightly lower than #1#, there is decay. This growth or decay is sharper if the base is farther from #1# on either side.

For #f(x)=32(0.5^x)#, the graph appears as below.

graph{32(0.5^x) [-16.88, 23.12, -7.24, 12.76]}