# Does zinc react with NaOH when its not heated?

Sep 1, 2017

Zinc is an active metal.......

#### Explanation:

It will slowly be oxidized by hydroxide, to give $Z {n}^{2 +}$ and dihydrogen gas......

And we could write the redox couple....

$Z n \rightarrow Z {n}^{2 +} + 2 {e}^{-}$ $\left(i\right)$

${H}_{2} O + {e}^{-} \rightarrow \frac{1}{2} {H}_{2} \left(g\right) \uparrow + H {O}^{-}$ $\left(i i\right)$

And so we take $\left(i\right) + 2 \times \left(i i\right)$ to get......

$Z n \left(s\right) + 2 {H}_{2} O \left(l\right) \rightarrow Z {n}^{2 +} + 2 H {O}^{-} + {H}_{2} \left(g\right)$

In conc. hydroxide it would probably from the zincate ion, ${\left[Z n {\left(O H\right)}_{4}\right]}^{2 -}$.....

$Z n \left(s\right) + 2 H {O}^{-} + 2 {H}_{2} O \left(l\right) \rightarrow Z n {\left(O H\right)}_{4}^{2 -} + {H}_{2} \left(g\right) \uparrow$